trisharog Posted November 1, 2010 Share Posted November 1, 2010 Yikes! I could really use help with this problem: Jenny had 250 more local stamps than Malayasian stamps. After giving 76 local stamps to her friend, she had 1/4 as many Malaysian stamps as local stamps. How many local stamps did Jenny have at first? Thanks Trisha Quote Link to comment Share on other sites More sharing options...
DragonFaerie Posted November 1, 2010 Share Posted November 1, 2010 Hm. I'm no math wiz but this is as far as I got with it: x = the number of Malaysian stamps x + 250 = the number of local stamps But the next part threw me: x + 174 = the number of local stamps after the give away so the equation would be (I think) x + 174 = .25x but I have no idea how to solve that. Then again, I was an English major so I could be WAAAAYYYY off. :tongue_smilie: Oh wait.. maybe it's .25(x + 174) = x? Hmmm.... Quote Link to comment Share on other sites More sharing options...
Halcyon Posted November 1, 2010 Share Posted November 1, 2010 (edited) love these bar graph problems LOL Edited November 1, 2010 by Halcyon Quote Link to comment Share on other sites More sharing options...
AngieW in Texas Posted November 1, 2010 Share Posted November 1, 2010 This must be a Singapore problem, because I remember helping one of my girls with it at some point. Jenny had 250 more local stamps than Malayasian stamps. After giving 76 local stamps to her friend, she had 1/4 as many Malaysian stamps as local stamps. How many local stamps did Jenny have at first? Draw your rod diagrams like this: starting condition: [------local-stamps-][------------------------------250----------------------------] [-Malaysian-stamps-] ending condition (after giving her friend 76 of her local stamps): [-----local-stamps--][---------------------174-----------------------] [-Malaysian-stamps-] Now there are 1/4 as many Malaysian stamps as local stamps. That means that 174 has to be equal to 3x the number of Malaysian stamps, so there have to be 174/3 = 58 Malaysian stamps. Quote Link to comment Share on other sites More sharing options...
DragonFaerie Posted November 1, 2010 Share Posted November 1, 2010 Well, my equation works with plugging in the 58 for x. But I still have no idea how I would have solved it. LOL Quote Link to comment Share on other sites More sharing options...
Adrianne in TX Posted November 1, 2010 Share Posted November 1, 2010 Angie Will you teach my kids math to the end of time...watch what you answer...I will see you again :) Adrianne Quote Link to comment Share on other sites More sharing options...
Tattarrattat Posted November 1, 2010 Share Posted November 1, 2010 (edited) Well, my equation works with plugging in the 58 for x. But I still have no idea how I would have solved it. LOL Using algebra, If x = malaysian stamps, then x+(250-76)= 4x, x=58, local stamps before = 58+250=308 * At the end, local stamps were 4 times of Malaysian stamps, not 1/4 of Malaysian stamps. Or if you choose to use x= local stamps in the begining, then 4(x-250)= x-76, 3x=924, x=308 Edited November 1, 2010 by Tattarrattat add alternative method: x=local stamps in the beginning Quote Link to comment Share on other sites More sharing options...
trisharog Posted November 1, 2010 Author Share Posted November 1, 2010 thx everyone! Quote Link to comment Share on other sites More sharing options...
Testimony Posted November 1, 2010 Share Posted November 1, 2010 First, he estimated about 300 as the answer. Next, he figured that 2X+250-76=2x+174 Then, he divided 174 by 3 because of this bar diagram: [][][][/] He cancelled the last bar here. [/] He cancelled this bar. That's how he got 3 bars. He got 58 when dividing 174/3. Then he multiplied 58X4=232+76=308. So, it was close to the estimation. Just another way of looking at it based on a 12 year old's thinking. Blessing in your homeschooling journey. Sincerely, Karen http://www.homeschoolblogger.com/testimony Quote Link to comment Share on other sites More sharing options...
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