Heartsjoy Posted October 29, 2013 Share Posted October 29, 2013 I need to see a bar diagram for this singapore 6CWP problem. p. 27 11. The usual selling price of a car was $104,000. It was later sold at a 10% discount and a 17% profit was made. Find the loss that would have been made if it had been old at a 30% discount. The answer is $7200 according to the book. Any one for bar diagrams? Quote Link to comment Share on other sites More sharing options...
Monica_in_Switzerland Posted October 29, 2013 Share Posted October 29, 2013 Ok, I got the right answer (phew), this is how I did it: Original Price ---------------------------104,000---------------------------- Sale Price ------------------------- 90% ------------------¦-----10%---- At this point I figured out the sale price: 104000 * .9 = 93,600 Sale Price = Factory Price + Profit ---------------------93600---------------------------------- -------Factory Price (100%)----¦---Profit (17%)------ Factory Price = 93600/1.17 Factory Price = 80000 Had it been sold at a 30% discount, the price would have been 104000 * .7 = 72800 Loss at that price would have been the difference between factory cost and the sale price 80000 - 72800 = 7200$ I hope that makes sense- I'm not sure how they teach it at that level because we haven't gotten there yet! Quote Link to comment Share on other sites More sharing options...
nansk Posted October 29, 2013 Share Posted October 29, 2013 I solved the problem this morning, but didn't see how bar diagrams made it any easier to solve. There are some word problems, where just looking at the bar diagram, you can see the answer. This one was not like that. Quote Link to comment Share on other sites More sharing options...
EKS Posted October 29, 2013 Share Posted October 29, 2013 I solved the problem this morning, but didn't see how bar diagrams made it any easier to solve. There are some word problems, where just looking at the bar diagram, you can see the answer. This one was not like that. :iagree: Quote Link to comment Share on other sites More sharing options...
boscopup Posted October 29, 2013 Share Posted October 29, 2013 I wouldn't have used bar diagrams for this problem either. They don't really add to the ability to solve this problem. (and I love bar diagrams) Quote Link to comment Share on other sites More sharing options...
Heartsjoy Posted October 30, 2013 Author Share Posted October 30, 2013 Thanks ladies. I just didn't understand loss. Quote Link to comment Share on other sites More sharing options...
letsplaymath Posted October 30, 2013 Share Posted October 30, 2013 The most important step in solving any percent problem is to figure out what quantity is being treated as the basis, the whole thing that is 100%. What makes this problem especially difficult is that the "whole" changes from one part of the story to the next. The discount is a percentage of the regular price (the cost to the customer), but the profit or loss is a percentage of what the item cost the store. For more help in sorting out percent problems: Percents: The Search for 100% Quote Link to comment Share on other sites More sharing options...
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