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A math question regarding exponents ........


Miss Sherry
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You can also see that a^0 has to be one for other exponential rules to work.

 

For instance, a^m * a^n = a^(m+n)

So if you have 5^3 * 5^6 = 5^9

 

Now if you had 5^2 * 5^0 = 5^(2+0) = 5^2.

The only thing you can multiply 5^2 by to get itself is 1.

Therefore for the product rule to stay correct, we have to define a^0 = 1.

(Note only true if a isn't 0.)

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I've also seen it explained:

 

10^5 = 1 with 5 zeros, thus 100,000

10^4 = 1 with 4 zeros, thus 10,000

10^3 = 1 with 3 zeros, thus 1,000

10^2 = 1 with 2 zeros, thus 100

10^1 = 1 with 1 zero, thus 10

10^0 = 1 with 0 zeros, thus 1

 

and also this way:

 

3^5 means 3 times itself 5 times

3^4 means 3 times itself 4 times

3^3 means 3 times itself 3 times

3^2 means 3 times itself 2 times

3^1 means 3 times itself 1 time

3^0 means 3 times itself 0 times, which "by default" or simply "by definition" is 1

Edited by daybreaking
to correct a typo
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I can see that 10^0 is 1 but it still doesn't make sense in my mind that all other numbers to the power of zero = 1.

I see that Dana said it makes other exponential equations work so I will just have to keep it memorized for now.

 

5^4 = 5^3 * 5

5^3 = 5^2 * 5

5^2 = 5^1 * 5

5^1 = 5^0 * 5

5^0 = 5^-1 * 5 which is: (1/5 * 5) = 1

5^-1 = 5^-2 * 5 which is: (1/25 * 5) = 1/5

etc.

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