Aloha2U Posted September 17, 2020 Posted September 17, 2020 What are the steps not shown in this solution? We are missing something. Can anyone explain this to us? Please help! Evaluate the function at the given value(s) of the independent variable. Simplify the results. Quote
RootAnn Posted September 17, 2020 Posted September 17, 2020 Sorry it is sideways. My answer is a simplified a bit differently but hopefully you can catch whatever you were confused about in the middle steps? Quote
Aloha2U Posted September 17, 2020 Author Posted September 17, 2020 HUGE help! HUGE! You have saved our sanity! 1 Quote
RootAnn Posted September 18, 2020 Posted September 18, 2020 (edited) Speaking of which, @square_25, why did they multiply by 1 +(x-1)^(1/2) over 1+(x-1)^(1/2)? I would probably have simplified at that point by trying to get rid of the square root in the denominator. Edited September 18, 2020 by RootAnn Fixed a sign Quote
RootAnn Posted September 18, 2020 Posted September 18, 2020 I don't really see where getting rid of the x-2 in the denominator is any better than getting rid of the square root there. That's why I asked. If it ended up looking any better at the end, I'd understand. I feel like: (X-1)^(1/2) - x - 1 ------------------ (x-2)(x-1) Seems just as decent an answer. :) But, I guess that would mean x couldn't equal 2 or 1 whereas with thetirs, x just can't equal 2. Speaking of which, I find it humorous how they plug 2 in for x in the original function but in their equation, x cannot equal 2. ;) Quote
RootAnn Posted September 18, 2020 Posted September 18, 2020 Perfect. Thanks. That makes sense with OP's title of "preparation for Calculus." Quote
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