beansprouts Posted October 27, 2008 Share Posted October 27, 2008 (edited) Duplicate thread. Please post here. Edited October 27, 2008 by beansprouts Quote Link to comment Share on other sites More sharing options...
Jen500 Posted October 27, 2008 Share Posted October 27, 2008 You'd do this using the bar method-one bar for each pile. (I can't 'draw' it on the computer-maybe someone else can) We're in 4A also, and this is the first year I've really used the HIG a lot. It helps me explain the text in more depth. Sometimes there's only 1/4 page lesson in the text, and there's a much lengthier description in the HIG. CWP or IP is great for mastering these word problems too, and there are examples included. Quote Link to comment Share on other sites More sharing options...
at the beach Posted October 27, 2008 Share Posted October 27, 2008 (edited) Page 41 in the Textbook "Review A" problem #10: Up to this point, I have been very comfortable with the math and not found a need for the teacher's manual. There have been a few problems like these, and I am not seeing how they relate to the preceding lessons. I know how to solve the problems algebraically (pile #3 is x, pile #2 is 2x, pile #1 is 2x+10) and this is what I taught dd. She caught on to this and was able to finish the problem. However, if she was supposed to learn an entirely different skill, I don't want to skip it. How would you handle this with a 9 1/2 year old 5th grader? As this program becomes more advanced, am I going to run into more situations where the TM would be helpful? Okay, let me take a stab at this. I think this is how it would be done. Please someone correct me if I am wrong! 3000 books in all, so we will have three bars/piles. Bar 1 will have 10 more books than Bar 2, and Bar 3 will be exactly half of Bar 2 because Bar 2 is twice of Bar 3. So, taking that into account, here is how I would set it up. Bar 1 __________________ ___________________ ___ Bar 2 __________________ ___________________ Bar 3 __________________ So, now we can see that if there are 3000 books in all and each of the units shown is equal but Bar 1 has ten more we need to figure out how to divide 3000 between the bars. We take out 10 because that's already accounted for in Bar 1--the small line. Then, when we divide up 2990 by 5, the answer for each bar is 598. Then, from that we can see that pile 3 has 598 books in it. The reason the first bar ends up cut in half is because we have had a quantity in Bar 3 that indicates 2 is twice of three. I tried to put numbers under my bars but in the preview it didn't appear right. Not sure what I am doing wrong or how to show it better. I would highly recommend the Home Instructor Guide sold by Sonlight. Best wishes-- Anita Edited October 27, 2008 by Violet Edited to take away 10 from 3000, not 100! Quote Link to comment Share on other sites More sharing options...
beansprouts Posted October 27, 2008 Author Share Posted October 27, 2008 I will order the HIG, it sounds like it will be useful at this point. Thank you :001_smile: Quote Link to comment Share on other sites More sharing options...
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