mama25angels Posted January 28, 2015 Share Posted January 28, 2015 Using book 4A and the HIG, but need the problem broken down a bit more for me, it's a word problem and a doozy: 3000 exercise books are arranged into 3 piles. The first pile has 10 more books than the second pile. The number of books in the second pile is twice the number of books in the third pile. How many books are there in the third pile? Thanks! Quote Link to comment Share on other sites More sharing options...
forty-two Posted January 28, 2015 Share Posted January 28, 2015 Drawing a bar diagram: [------1st------][---2nd----][-3rd] [-----][-----][10][-----][-----][-----] [---------------3,000--------------] You end up with the third pile as your unit. So: Third pile = 1 unit, Second pile = 2 units (twice the # in third pile) First pile = 2 units + 10 (ten more books than second pile) All the piles together equal 3,000 books, so: 2 units + 10 + 2 units + 1 units = 3,000 5 units + 10 = 3,000 5 units = 2,990 One unit = 598 books First pile = 2 units + 10 = 1206 books Second pile = 2 units = 1196 books Third pile = 1 unit = 598 books Check: 1206 + 1196 + 598 = 3,000 (and a good thing I did the check, too, because I had a math error and that would have been embarrassing ;)) Answer: The third pile has 598 books in it. Does that make sense? Quote Link to comment Share on other sites More sharing options...
ikslo Posted January 28, 2015 Share Posted January 28, 2015 (2x+10)+2x+x = 3000 5x+10=3000 5x=2990 x=2990/5=598 Quote Link to comment Share on other sites More sharing options...
mama25angels Posted January 28, 2015 Author Share Posted January 28, 2015 Thank you ladies Quote Link to comment Share on other sites More sharing options...
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