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Can anyone help me with this math problem?


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This is a rate problem. Rate x time = job. Bob's rate is 1 job/4hours. Sally's rate is 1 job/6hours.

 

Together :

Bob's rate x time for job + Sally's rate x time for job = job

(1 job/4 hours) x time + (1 job/6 hours) x time = 1

1/4 t + 1/6 t = 1

Finding common denominators:

3/12 t + 2/12 t =1

5/12 t = 1

t = 12/5 = 2.4 hours

 

Does that make sense?

 

Linda

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This is a rate problem. Rate x time = job. Bob's rate is 1 job/4hours. Sally's rate is 1 job/6hours.

 

Together :

Bob's rate x time for job + Sally's rate x time for job = job

(1 job/4 hours) x time + (1 job/6 hours) x time = 1

1/4 t + 1/6 t = 1

Finding common denominators:

3/12 t + 2/12 t =1

5/12 t = 1

t = 12/5 = 2.4 hours

 

Does that make sense?

 

Linda

 

This makes sense, but I like this answer better: :lol:

 

 

I guess it would take 8 hours because Bob will sit back with his i-phone while Sally complains for 2 hours about Bob not helping her before she finally just gets fed up and does it by herself.

 

 

 

 

 

 

:lol:

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If it takes Bob 4 hours to complete a job, and it takes Sally 6 hours to do the same job, how long will it take if they both work together?

 

How do you figure this out? Can someone 'splain it to me?

 

I think the most common error is when people average the times and say 5 hours. The trick to avoiding this mistake is to realize that if Sally heads out and goes shopping, the job will be done in 4 hours by Bob, so if they're working together (and not getting in each other's way) the job will be done in LESS time than it would take the fastest one alone. (It's not like when a child helps you with a household chore.)

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