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Need help with bar diagrams. SM 4


heart'sjoy
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Can anyone show us how to draw the bar diagrams for this sm problem ? I've filled 4 sheets of graphpaper and still don't see the units.

 

 

4 books and 5 magazine cost $103.60 altogether. 8 books and 3 magazines cost $134.40 altogether. How much less does each magazine cost than each book?

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What problem is it?

 

Just looking at what you wrote and not our book, I bet we doubled the first equation to 8 books and 10 magazines cost $207.20. Then since both equations have 8 books, the only difference in cost is due to 7 more magazines in the first and use that to figure out the cost of one magazine. That's a very algebraic approach--not sure if we did a bar diagram or not.

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What problem is it?

 

Just looking at what you wrote and not our book, I bet we doubled the first equation to 8 books and 10 magazines cost $207.20. Then since both equations have 8 books, the only difference in cost is due to 7 more magazines in the first and use that to figure out the cost of one magazine. That's a very algebraic approach--not sure if we did a bar diagram or not.

 

It's CWP 4 p82 #23.

 

I'm looking at it and not figuring it out :)

I'd set up a system of equations:

4b + 5m = 103.60

8b + 3m = 134.40

Doubling the first eqn and finding the difference will solve for a magazine price.

 

No idea how to use bar diagrams. I'll be curious to see how it works out!

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I bow to the math nerds on this site. I'm not coming up with a nice number. Maybe I've forgotten my algebra. :glare: I even tried doubling the equation and all. I don't have any idea how you'd translate this into a bar diagram for a kid. I'm so glad I don't have the kids doing CWP. It's too hard for me!

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4 books and 5 magazine cost $103.60 altogether. 8 books and 3 magazines cost $134.40 altogether. How much less does each magazine cost than each book?

 

I would double the first scenario:

 

8 books and 10 magazines cost $207.20

 

The difference between this 8:10 and the acutual 8:3 is 7 units/magazines.

 

You would see this if you drew the original 4:5 and then drew the 8:3 ratio. You need to keep the ratio the same to figure out the problem.

 

 

difference in cost is 207.20-134.40 is 72.8. Divide this by the number of units that are different between the doubled scenario and the actual (7) to get a single unit (10.40 per magazine). In the original equation, 5 would cost 52.00 and the 4 books would cost (103.60-52)/4 = 12.90.

 

So each book cost $2.50 more than each magazine.

 

I'm probably not explaining this clearly, but these CWP problems require a lot of mental/logic to figure out.

Edited by NicksMama-Zack's Mama Too
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[———————$207.20———————]

|———8B———|————10M————|

[——$134.40————]

|———8B———|—3M|

|———————————[——$72.80—]

|———————————|———7———|

 

72.80/7 = $10.40 cost per magazine

8B + 3(10.40) = 134.40

8B + 32.10 = 134.40

B = 103.20/8 = $12.90 cost per book

Cost difference = $2.50

 

Jackie

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[———————$207.20———————]

|———8B———|————10M————|

[——$134.40————]

|———8B———|—3M|

|———————————[——$72.80—]

|———————————|———7———|

 

72.80/7 = $10.40 cost per magazine

8B + 3(10.40) = 134.40

8B + 32.10 = 134.40

B = 103.20/8 = $12.90 cost per book

Cost difference = $2.50

 

Jackie

 

:) Very Nice!

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[———————$207.20———————]

|———8B———|————10M————|

[——$134.40————]

|———8B———|—3M|

|———————————[——$72.80—]

|———————————|———7———|

 

72.80/7 = $10.40 cost per magazine

8B + 3(10.40) = 134.40

8B + 32.10 = 134.40

B = 103.20/8 = $12.90 cost per book

Cost difference = $2.50

 

Jackie

 

Boy, that makes it look so easy!

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[———————$207.20———————]

|———8B———|————10M————|

 

[——$134.40————]

|———8B———|—3M|

 

|———————————[——$72.80—]

|———————————|———7———|

 

72.80/7 = $10.40 cost per magazine

8B + 3(10.40) = 134.40

8B + 32.10 = 134.40

B = 103.20/8 = $12.90 cost per book

Cost difference = $2.50

 

Jackie

 

Many thanks

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