Cindy in FL. Posted July 28, 2010 Share Posted July 28, 2010 Could anyone help my ds answer the following math problem? TRM and KBV are similar triangles. The ratio of RM to BV is 3:2. What do you know about the relationship between TR and BV? Explain. My poor brain is just not getting it right now. Thanks for any help! Cindy Quote Link to comment Share on other sites More sharing options...
Jann in TX Posted July 28, 2010 Share Posted July 28, 2010 This is a strange problem--but I've seen them before... Since the triangles are similar, each pair of corresponding sides will have the same 3:2 ratio. Mark RM=3 and BV=2 We do not know the actual measures of TR and KB... but we do know their ratio is 3:2 so TR=3X and KB=2X BV is already marked BV= 2 so: The ratio of TR to BV is 3X:2 Quote Link to comment Share on other sites More sharing options...
Cindy in FL. Posted July 28, 2010 Author Share Posted July 28, 2010 It is an odd sort of problem. I was telling him that each of the corresponding pairs were "equal" in the sense of their ratios, but trying to explain it is difficult for him. Thank you for your response, he seemed to get it. Cindy Quote Link to comment Share on other sites More sharing options...
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