Osmosis Mom Posted January 18, 2011 Share Posted January 18, 2011 Stumped and needing help with this: (4k^4 + 6k^3 + 3k - 1)/(2k^2 + 1) Can anyone help? Quote Link to comment Share on other sites More sharing options...
kiana Posted January 18, 2011 Share Posted January 18, 2011 Rewrite the numerator as 4k^4 + 6k^3 - 2k^2 + 2k^2 + 3k - 1, then group into two groups of three and factor by grouping. Quote Link to comment Share on other sites More sharing options...
Krista in LA Posted January 18, 2011 Share Posted January 18, 2011 I couldn't get this to format right without putting the "." in there. I hope I'm remembering correctly, but I would do it just by dividing it out ..............2k^2 + 3k - 1 .............._________________________ 2k^2 + 1 )4k^4 + 6k^3 + 0k^2 + 3k - 1 ..............4k^4........... + 2k^2 ..............__________________________ .........................6k^3 - 2k^2 + 3k - 1 .........................6k^3.......... + 3k ..............__________________________ ................................ - 2k^2 .......- 1 ................................ - 2k^2 .......- 1 .............. __________________________ .................................................... 0 Quote Link to comment Share on other sites More sharing options...
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