Caitilin Posted October 21, 2010 Share Posted October 21, 2010 (edited) Please!! 300 children are divided into 2 groups. One group has 50 more children than the second group. How many are in each group. I know how to solve this problem algebraically, but I don't know how to do it with the Singapore bar graphs. Can anyone help me explain this to ds? Edited October 21, 2010 by Caitilin Quote Link to comment Share on other sites More sharing options...
Dana Posted October 21, 2010 Share Posted October 21, 2010 I'd draw two bars equal in length labeled 150 for the first part. Then take off part from one bar (shading) and add to the other (extend). The difference is 50, so each shaded and extended part is 25. So one group has 175 and the other has 125. Quote Link to comment Share on other sites More sharing options...
Jackie in AR Posted October 21, 2010 Share Posted October 21, 2010 Please!! 300 children are divided into 2 groups. One group has 50 more children than the second group. How many are in each group. I know how to solve this problem algebraically, but I don't know how to do it with the Singapore bar graphs. Can anyone help me explain this to ds? Your bar should have two units of (unknown) equal length, and then an extra unit at the end that equals 50. 300 - 50 = 250 250/2 = 125 for each of the equal length units Group 1 = 125 children Group 2 = 125 + 50 = 175 children Quote Link to comment Share on other sites More sharing options...
Caitilin Posted October 21, 2010 Author Share Posted October 21, 2010 Thanks, ladies! Quote Link to comment Share on other sites More sharing options...
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