smdgl Posted December 18, 2013 Share Posted December 18, 2013 Can anybody tell me if there is an error in Example 8.10? In the middle of page 251, we think the equilibrium equation should be: (3.80-x)^2 2.5 X 10^3 = _________________ (0.5*x)(0.20+x)^2 The book shows the numerator without an exponent. Contrast the explanation for the OYO 8.10 which seems to be essentially the same problem. In that case, the numerator does include the exponent 2. Any insight? If there is an errata available anywhere, I could not find it. Has anyone made their own? Thanks! Quote Link to comment Share on other sites More sharing options...
Dicentra Posted December 18, 2013 Share Posted December 18, 2013 If you could possibly scan in the whole question, I could tell you if their answer is correct or not. :) Without seeing the question, I can tell you that an exponent of 2 would be needed on that term if the compound that it's referring to has a coefficient of 2 in the balanced chemical equation. Does that help? Quote Link to comment Share on other sites More sharing options...
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