Arctic Bunny Posted October 24, 2016 Share Posted October 24, 2016 Can you think of another way to make 20 and 9 using only the numbers 2, 3, 4 once each and any combination of brackets, addition, subtraction, division and multiplication. No number 1, no exponents. So 20=4(2+3) and 9=2+3+4 Good luck! Quote Link to comment Share on other sites More sharing options...
Arctic Bunny Posted October 24, 2016 Author Share Posted October 24, 2016 So... Not yet? :) Quote Link to comment Share on other sites More sharing options...
regentrude Posted October 24, 2016 Share Posted October 24, 2016 (edited) I tried to approach this systematically. 9=3x3, the only way to factor. And you cannot create a factor 3 from the numbers 2 and 4 if each can be used only once. So it must be a sum, and since you use all three numbers, there should not be a different way. 20 =4x5=10x2. No other factors. There is only one way to make 5 from 2 and 3, the way you did. There is no way to make 10 from 3 and 4 with your restrictions. Numbers are too small to make 20 by addition or a sum of a number and a product of two numbers (12 is the largest product) So no, I do not think it is possible to express them differently within the given constraints (unnecessary parentheses and use of commutative property don't count as "different") ETA: If we lift the restriction that each number can be used only once, I see different ways. Edited October 24, 2016 by regentrude Quote Link to comment Share on other sites More sharing options...
hjffkj Posted October 24, 2016 Share Posted October 24, 2016 I tried to approach this systematically. 9=3x3, the only way to factor. And you cannot create a factor 3 from the numbers 2 and 4 if each can be used only once. So it must be a sum, and since you use all three numbers, there should not be a different way. 20 =4x5=10x2. No other factors. There is only one way to make 5 from 2 and 3, the way you did. There is no way to make 10 from 3 and 4 with your restrictions. Numbers are too small to make 20 by addition or a sum of a number and a product of two numbers (12 is the largest product) So no, I do not think it is possible to express them differently within the given constraints (unnecessary parentheses and use of commutative property don't count as "different") ETA: If we lift the restriction that each number can be used only once, I see different ways. What she said. Quote Link to comment Share on other sites More sharing options...
Arctic Bunny Posted October 24, 2016 Author Share Posted October 24, 2016 That's what I came up with, too. So glad our family isn't alone! I'm dying to see what happens when they correct at school tomorrow. Thanks guy So! Quote Link to comment Share on other sites More sharing options...
maize Posted October 24, 2016 Share Posted October 24, 2016 You'll have to update here! Quote Link to comment Share on other sites More sharing options...
eternalsummer Posted October 24, 2016 Share Posted October 24, 2016 There's a game that's great for this - it's a little spinner thing with dice in it called Numbler Jumbler. You can use each number once but you can do exponents (and must, pretty often). Here it is: Quote Link to comment Share on other sites More sharing options...
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