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Math challenge!


Arctic Bunny
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I tried to approach this systematically.

9=3x3, the only way to factor. And you cannot create a factor 3 from the numbers 2 and 4 if each can be used only once. So it must be a sum, and since you use all three numbers, there should not be a different way.

 

20 =4x5=10x2. No other factors. There is only one way to make 5 from 2 and 3, the way you did. There is no way to make 10 from 3 and 4 with your restrictions.

Numbers are too small to make 20 by addition or a sum of a number and a product of two numbers (12 is the largest product)

 

So no, I do not think it is possible to express them differently within the given constraints (unnecessary parentheses and use of commutative property don't count as "different")

 

ETA: If we lift the restriction that each number can be used only once, I see different ways.

Edited by regentrude
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I tried to approach this systematically.

9=3x3, the only way to factor. And you cannot create a factor 3 from the numbers 2 and 4 if each can be used only once. So it must be a sum, and since you use all three numbers, there should not be a different way.

 

20 =4x5=10x2. No other factors. There is only one way to make 5 from 2 and 3, the way you did. There is no way to make 10 from 3 and 4 with your restrictions.

Numbers are too small to make 20 by addition or a sum of a number and a product of two numbers (12 is the largest product)

 

So no, I do not think it is possible to express them differently within the given constraints (unnecessary parentheses and use of commutative property don't count as "different")

 

ETA: If we lift the restriction that each number can be used only once, I see different ways.

What she said.

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