Gil Posted January 26, 2016 Posted January 26, 2016 Write the missing value in each trinomial s^2 - 10s - 20 = (s + 2) (s + [_]) I was working with a tutee today and we were going over their homework together. There were several sections on the packet and when we got to this section I could do all of the problems like this one within 5-10 seconds without writing it down but this one stomped me and its bothering me. What am I missing? Is this a typo or is my brain just puttering out on me? (This worksheet DID have a few obvious typos in a couple of other problems.) Quote
Tsuga Posted January 26, 2016 Posted January 26, 2016 That is a typo. You can always check by punching it into a calculator: http://www.mathportal.org/calculators/polynomials-solvers/polynomial-factoring-calculator.php I mean don't tell your tutee... ;) 1 Quote
Arcadia Posted January 26, 2016 Posted January 26, 2016 Typo error. I am guessing s^2 - 10s - 20 = (s + 2) (s + [_]) to be s^2 - 10s - 24 = (s + 2) (s + [_]) and the blank to be -12 1 Quote
Gil Posted January 26, 2016 Author Posted January 26, 2016 Thanks, I thought it was a typo but couldn't accept that it the worksheet was wrong because my brain kept trying figure out which number was supposed to be wrong. (I didn't see it as s^2 - 10s - 24) I kept mentally adjusting for the 10s in the middle. I had graphed it by hand and I used the the quadratic formula on it and I KNEW that the problem didn't make sense. This kid is roughly 2/3 of the way through Algebra 1 but he didn't know how to graph quadratics or use the quadratic formula yet. I wasn't sure how to explain to him how I knew that the worksheet was wrong so I kept looking for how *I* could be wrong. Quote
mathwonk Posted January 26, 2016 Posted January 26, 2016 (edited) a quick way to check this is wrong is to plug in s = -2 on both sides. you get zero on the right side where there is afactor of (s+2), but you don't get zero on the left, you get 4, so to make it work you have to subtract off another 4 on the left. edit: In my opinion, this is probably the most important principle in algebra, called the "root - factor" theorem. I.e. given any polynomial f(x), the linear term (x-a) is a factor of f(x) if and only if x=a is a root, i.e. iff f(a) = 0. Edited January 27, 2016 by mathwonk 2 Quote
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