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Given w = 10, what is the answer to w + (w – 12 ÷ 22 • 3) • 7

 

I got 73, the test said its wrong and the answer is 17

 

 

 

Are you missing a set of parentheses? Because how you group the stuff in the existing parens will affect your answer.

 

((w-12)÷(22*3) or (w-(12÷22)*3) or (w-(12÷(22*3)))

 

Assume L-R (after PEMDAS) in the middle and you get 68.5 or something like that, so still not a matching answer :tongue_smilie:

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Are you missing a set of parentheses? Because how you group the stuff in the existing parens will affect your answer.

 

((w-12)÷(22*3) or (w-(12÷22)*3) or (w-(12÷(22*3)))

 

Assume L-R (after PEMDAS) in the middle and you get 68.5 or something like that, so still not a matching answer :tongue_smilie:

 

Can I just say I'm so excited to see I got the "wrong" problem "right"?!

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Assuming answer is 17,

 

w + (w – 12 ÷ 22 • 3) • 7 = 17

 

Substituting w = 10,

10 + (10 – 12 ÷ 22 • 3) • 7 = 17

(10 – 12 ÷ 22 • 3) • 7 = 7

(10 – 12 ÷ 22 • 3) = 1

12 ÷ 22 • 3 = 9 which is not possible

 

 

I got 68.5 too.

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umm... a duh moment 22 should be 2 to the 2nd power. Don't know how to write that here

 

I've seen that written 2^2 before

 

However, I'm not sure how readable that would be for most.

 

 

So:

w + (w – 12 ÷ 2^2 • 3) • 7 where w=10

 

w + (w-12 ÷ 4 * 3) *7

w+ (w- 3 * 3) * 7

w + (w-9) * 7

10 + (10-9) * 7

10 + 1 * 7

10 + 7

17

 

Multiplication an division are at the same level of order of operations, you do them L to R otherwise

Similarly, addition and subtraction are at the same level.

Edited by vonfirmath
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Given w = 10, what is the answer to w + (w – 12 ÷ 22 • 3) • 7

 

I got 73, the test said its wrong and the answer is 17

 

this did not C&P correctly, the 22 should be an exponent of 2 to the 2nd power

 

The problem is:

w+(w-12 / 2^2 x 3) x 7

w = 10

 

You need to know Please Excuse (My Dear) (Aunt Sally) or PE(MD)(AS), the order of operations. It means first do whatever is in parenthesis, then exponents, then multiplication/division, then addition/subtraction. In all cases, work left to right. When you're working inside parenthesis, apply PE(MD)(AS) to just that part, then when you've gotten it down to one term with no operations, you start again with PE(MD)(AS) on the whole thing.

 

Substitute in the 10 for w:

10 + (10-12/2^2x3)x7

First, do the parenthesis. Start with PD(MD)(AS) again with what's inside the (). Inside them, there are no parenthesis, so do the exponent:

2^2 = 4, so

10 _ (10-12/4x3) x7

 

Then multiplication and division, moving left to right:

12/4 = 3, so

10 + (10-3x3) x 7

 

3 x 3 = 9, so

10 + (10-9) x 7

 

Then the addition/subtraction:

10-9= 1, so

10 + (1) x 7

 

You can now remove the (), because there are no more operations inside them:

10 + 1 x 7

 

Now, start over with PE(MD)(AS): no parenthesis, no exponents, so do the multiplication/division:

1 x 7 = 7, so

10 + 7

 

And now the adding/subtracting:

10+7 = 17, so the answer is:

17

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