Testimony Posted June 4, 2009 Share Posted June 4, 2009 I have been racking my brain out for two days. :banghead:I have a feeling that it is simple and I am missing it. Can anyone help me? Here's the problem: 5 books and 9 magazines cost $156 altogether. 9 books and 5 magazines cost $180 altogether. How much more does each book cost than each magazine? Does anyone have an idea how I can use a bar diagram or is it a ratio? I am stuck. Thank you all! Sincerely, Karen http://www.homeschoolblogger.com/testimony Quote Link to comment Share on other sites More sharing options...
babysparkler Posted June 4, 2009 Share Posted June 4, 2009 (edited) I'm too tired to do the math, but if you isolate one of the equations to solve for B or M, then plug it into the other equation, I think you should be able to solve it... 5b+9m=156 9b+5m=180 (1) isolate the second equation to solve for b: 9b+5m=180 9b=180-5m b=(180-5m)/9 (2) then plug the equivalent of "b" into first equation to solve for m: 5b+9m=156 5[(180-5m)/9]+9m=156 (3) Then solve for m... I could be off, but that is how I would start to attempt it. I wonder if there is a simpler way? Surely there has to be... Edited June 4, 2009 by babysparkler Quote Link to comment Share on other sites More sharing options...
plansrme Posted June 4, 2009 Share Posted June 4, 2009 (edited) I assume this is from Singapore CWP and you're supposed to solve w/o algebra. Each book cost $6 more than each magazine. Here's how: Set 1, $156, has 5 pair of books and magazines, plus 4 extra magazines, for $156. Set 2, $180, has 5 pair of books and magazines, plus 4 books, for $180. Set 2, with its 4 books instead of 4 magazines, costs $24 more than Set 1. Ergo, each books costs $6 more than each magazine. Use bar diagrams to show the matching of the "pairs" of books and magazines. 'Fraid that I have no idea how to show that accurately in this format. Terri Edited June 4, 2009 by plansrme Subtraction error Quote Link to comment Share on other sites More sharing options...
babysparkler Posted June 4, 2009 Share Posted June 4, 2009 That is MUCH easier than using the algebra ;) Quote Link to comment Share on other sites More sharing options...
Testimony Posted June 4, 2009 Author Share Posted June 4, 2009 It is from Singapore Math CWP 5. It is problem #20. So, yes it needs to be solved without algebra. Sorry.:tongue_smilie: Sincerely, Karen http://www.homeschoolblogger.com/testimony Quote Link to comment Share on other sites More sharing options...
plansrme Posted June 4, 2009 Share Posted June 4, 2009 That is MUCH easier than using the algebra ;) After Singapore 6 (and I don't think this is from 6, maybe 4), my daughter thought Algebra I was a breeze. She's in Alg. II now and still thinks Singapore 6 was the hardest math she's ever done. Terri Quote Link to comment Share on other sites More sharing options...
debbielong Posted June 4, 2009 Share Posted June 4, 2009 I remember that problem and it has been three years!!!!!! Quote Link to comment Share on other sites More sharing options...
Catwoman Posted June 4, 2009 Share Posted June 4, 2009 I just did it in my head to see if I could figure it out. Can someone tell me if the books cost $15 each and the magazines cost $9 each? I have no idea how I figured it out. DH always tells me that I have a weird way of looking at math, and my "non-methods" make no sense at all. Cat Quote Link to comment Share on other sites More sharing options...
Testimony Posted June 5, 2009 Author Share Posted June 5, 2009 I had a friend explain the bar diagram. It is : [/][/][/][/][/] books [][][][][/][/][/][/][/] magazines=$156 [/][/][/][/][/][][][][] books [/][/][/][/][/] magazines=$180 I crossed out 5 magazines to 9 magazines. I crossed out 5 books to 9 magazines. I am left with 4 books and 4 magazines. 180-156=24 $24/4=$6 It was simple. My son orginally got this answer and then erased it thinking it was wrong. I need a bar diagram. Thanks to everyone who help me solve it. Blessings, Karen http://www.homeschoolblogger.com/testimony Quote Link to comment Share on other sites More sharing options...
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