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Could someone help us with this Alg 2 problem?
mpcTutor replied to Storm Bay's topic in High School and SelfEducation Board
Download detail pdf solution: Train word problem Best regards. Mohan Pawar http://www.mpclasses.com/ContactUS.htm US Central Time:5:14 PM 9/27/2010 
Could someone help us with this Alg 2 problem?
mpcTutor replied to Storm Bay's topic in High School and SelfEducation Board
Please verify. I am getting Westward speed = 5 mph ( same as 5 miles per 60 min) Eastward speed = 7 mph (same as 7 miles per 60 min) I will try to post detail answer later if anyone interested. I have to go. Best regards. mpcTutor http://www.mpclasses.com/ContactUS.htm US Central Time:2:28 PM 9/27/2010 
How in the world do you simplify repeating
mpcTutor replied to mama25angels's topic in High School and SelfEducation Board
For solution see: How to represent a recurring decimal number as a rational number. Best regards. MPCtutor http://www.mpclasses.com/ContactUS.htm  AP Calculus, AP Physics, IIT JEE Test Prep.  US Central Time:1:28 PM 9/17/2010 
Need Compound interest math help
mpcTutor replied to mama25angels's topic in High School and SelfEducation Board
The previous poster already gave the solution. Here are details. Simply follow the same logic that you used for other problems solved correctly. If P = Present amount = 55000 i% = % interest rate per period (Note that I deliberately wrote per period and not per year ) = 8%/4 = 2% n = No. of periods for which P is in the saving account = 2 years x 4 period per year = 8 S = Lump sum amount yielded at the end of n period = To be found yield = interest paid on investment Then S = P( 1 + i%)^n (One can easily derive this formula with 7th grade algebra background. Note 2% = 2 per cent = 2/100 = 0.02)) = 55000 ( 1 + 0.02)^8 = 64441.27 Yield = 64441.27  55000 = 9441.27 (Answer) Best regards. mpcTutor http://www.mpclasses.com/ContactUS.htm  SAT/ACT, AP Calculus, AP Physics, IIT JEE Test Prep.  US Central Time:1:49 PM 9/16/2010 
any geometry proofers
mpcTutor replied to Supertechmom's topic in High School and SelfEducation Board
Your son is right and I don't see anything wrong with his proof. Although, problem asks to prove CA > CO, the zipped figure to me showed CA significantly shorter than CO without making any actual measurements. Also, triangles should appear to be congruent without actually measuring any sides or angles. So I am assuming the original diagram could be different from diagram in your attachment. Short Proof:  Given: OCE & ANE as congruent triangles Consider triangle OCE, OC < CE + EO (due to triangle inequality) OC < CE + EA (due to Given, EA = EO) OC < CA (due to betweeness of points CA = CE + EA ) QED Best regards. mpcTutor www.mpclasses.com  AP Calculus, AP Physics, Singapore Math Grades 712  Note: If you replied to my post but didn't get an answer from me in reasonable time, I ask you to check the assumptions in your question. Thank you US Central Time: 11:30 AM 7/29/2010 
(Note: Underlined words are links) I am not sure if I fall in any groups that you expected to respond. But I am not surprised that there has been no reply to your post yet. I volunteered to provide solutions to problems from AP Calculus and AP Physics on Feb 3, 2010. Note that Feb to May is THE most critical time for AP student's life cycle of AP test preparation but not a single problem from AP Calculus/Physics has yet been posted. Looks like not many students do calculus with a goal to take AP Calculus test given annually in May. There was a little change in Free Response Questions (FRQ) type problems. In the past, almost always there has been a problem from kinematics which was missing in the recent AP Calculus test and it might have surprised some students and teachers. Since you are looking for preparatory material, consider the current trends in test pattern. New trend suggests that one cannot count just on the wordbased familiarity with known AP problems. The same problem from kinematics can be presented under different wrapping. To answer your question, see the list of books that College board has given on their web site. College Board does give student and teacher lot of freedom in choosing material by stating "Not using a book from this list does not mean that a course will not receive authorization". After citing all this information, I must say that I myself have not yet adopted any of the books from above list of books. But I do recommend to get AP Calculus test problems from the College Board itself. I don't represent College Board and have no business gains or losses from their sales or no sales. My recommendation is based entirely on common sense: if certain universities need a good score in AP Calculus test, it makes sense for student family to know what the AP Calculus test is from the body that administers it. Certainly tests don't substitute the textbook but still I don't have recommendation for textbook. Students that I have been tutoring do use 9001100 page textbooks which they never have time to read. It is understandable that teachers use the textbook mostly to assign problems and the publisher has teacher's solution manual. Most of these books will give indiscriminately overwhelming number of problems at the end of each chapter that even when student has access to solution manual or to online solutions, there is never enough time to master the concepts in sufficient depth to be able to solve similar problems if seen on test. Unusual as it may sound but do consider physical weight of the calculus textbook before you buy one. Best regards. mpcTutor www.mpclasses.com  AP Calculus, AP Physics, Singapore Math Grades 712  Note: If you replied to my post but didn't get an answer from me in reasonable time, I ask you to check the assumptions in your question. Thank you US Central Time: 12:15 PM 5/21/2010 Edited at US Central Time: 12:15 PM 5/21/2010

Solution: Given:3x + y + z = 2 (1) 4x + 2z = 1(2) 5x  y + 3z = 0(3) If y is eliminated from (1) and (3) we get 8x + 4z = 2 (4) The resulting system now has Eq (2) and (4) which represent only one straight line. These equations are called as "dependent equations* in x and z". Values of x and z will depend on y and can be infinitely many depending on value of y. Thus, The strategy is not to eliminate y but eliminate x or z. (1) x 3  (3) gives 2x + 2y = 3 Thus x = (3 2y)/2 (Answer1) Substituting x from Answer1 in (2) 4(3 2y)/2 + 2z = 1 Thus, z = 5/2 + 2y (Answer2) and y = y  (Answer3) Now for any given value of y the given eqns (1), (2) and (3) will be uniquely satisfied. Dependent Equations:  See Eq (2) & (4). 4x + 2z = 1 and 8x + 4z = 2 are dependent because (4) depends on (2) and vice versa. Such equations are ignored when solving system of simultaneous equations and that's what is done above. Best regards. mpcTutor www.mpclasses.com  AP Calculus, AP Physics, Singapore Math Grades 712  US Central Time: 10:58 PM 5/18/2010 Edited at US Central Time: 7:12 AM 5/19/2010

physics problem please help!!
mpcTutor replied to 1cat2ferrets's topic in High School and SelfEducation Board
I gave this solution in hurry, please wait for someone to point out if any errors. Your book formula is correct. Use V for volts, N for turns, subscript p for primary and subscript s for secondary. Rewrite the formula as below: Vs/Vp = Ns/Np Hence Ns = Np (Vs/Vp) > (1) Given: Vp = 120,000 volts Vs = 120 volts Np = 1000 turns Substituting above quantities in (1) Ns = 1000 (120/120000) = 1 Current in secondary Is = Vs/Rs = 120/10 = 12 ampere c. what is the power in the secondary coil? Power in Watts Ps = Vs x Is = 120 volts x 12 ampere = 1440 watts Power in primary coil = Power in secondary coil Ip x Vp = Is x Vs = 1440 Ip = 1440/120000 = 0.012 ampere (which is comparatively low amperage) P ower loss = (I^2) R. Thus, power loss increases in square proportion of current I for a given resistance R. By reducing I to low level such as 0.012, the power companies avoid power loss during power delivery from power station which is far away fro home or place of power consumption. Rigorous solution to similar question is in math forum . ( See the link ) Best regards. mpcTutor www.mpclasses.com  AP Calculus, AP Physics, Singapore Math Grades 712  US Central Time: 2:43 PM 5/18/2010 
Reference to Saxon algebraII automatically assumes two more separate books as part of curriculum  i) AlgebraI and ii) Geometry. The switch from New Elementary Math (NEM) to Saxon is tricky unless one has already taught before the entire high school math including precalculus. The difficulty is due to Geometry/CoOrdinate Geometry, Trigonometry and AlgebraII being covered all along in the NEM up to book 4A. On the other hand, NEM 1, 2, 3 and 4A should be more than adequate for ACT + SAT and sufficient for subjects tests SAT Math Levels 1 & 2. For a brief inside view of Saxon's Advanced Math you may want to visit Amazon. Best regards. MPCTutor www.mpclasses.com  AP Calculus, AP Physics, Singapore Math Grades 712  US Central Time: 9:58 AM 5/17/2010

That's odd  I was able to find the table of contents and sample pages for the Singapore books here:Book 3A http://www.singaporemath.com/ProductDetails.asp?ProductCode=NEMT3A&Show=TechSpecs Book 3B http://www.singaporemath.com/ProductDetails.asp?ProductCode=NEMT3B&Show=TechSpecs Book 4A http://www.singaporemath.com/ProductDetails.asp?ProductCode=NEMT4A&Show=TechSpecs Book 4B http://www.singaporemath.com/ProductDetails.asp?ProductCode=NEMT4B&Show=TechSpecs If you were referring to the Saxon math books, then I would agree: I couldn't find similar info on their website. 69 Thanks for the links in support. Best regards. MPCTutor www.mpclasses.com  AP Calculus, AP Physics, Singapore Math Grades 712  US Central Time: 9:46 AM 5/17/2010

I have not seen Saxon math beyond Algebra 1/2 so it is difficult for me to compare. Like Singapore math very few textbooks make their basic information such as table of contents and a sample topic pages available on their websites for the buyer to evaluate the book. Most of word problems in the placement test are comparable to those in New Elementary Math (NEM). In fact, majority of challenging problems from "Challenging Word Problems (CWP)  Primary 6" from Singapore Math are harder than SAT/ACT word problems if one has do them in limited time. But CWP is another book. There are many many problems in NEM so I have not used any additional NEM workbooks. NEM could be too much as supplement.  NEM volume 3 & 4 are actually 4 separate books  3A/3B and 4A/4B with respectively 220, 240, 129 and 255 pages (i.e. a total of almost 850 pages). 4B with 255 pages is entirely problems for practice covering almost all important elementary, middle and high school math. Along with Saxon say, Algebra 1/2 which requires one to do all 30 problems per lesson, the NEM as supplement could be lot of work. Currently, I am using Singapore Math for 6th grade for students with Saxon Algebra 1/2 as their regular curriculum and it is lot of work for them. Unless criterion of evaluation of curriculum effectiveness is known, choosing a curriculum is going to be rather subjective. One can choose any of the NATIONAL level standardized tests as criterion. Most colleges use them as criterion for admissions. So why not use test prep books as supplement? For example, A book titled "Real ACT prep guide" will give almost 180 math problems that once were on real ACT. Similarly, one can choose SAT prep books from College Board or from some other publisher. Best regards. MPCTutor www.mpclasses.com  AP Calculus, AP Physics, Singapore Math Grades 712  US Central Time: 10:18 AM 5/15/2010

Concept is nothing but certain concrete idea (as against a vague notion). It doesn't matter if the concept is in mathematics or not, the success in identifying "the" concept from all other seemingly similar concepts is needed in understanding that particular concept. Example 1: Explain "All squares are rectangles but all rectangles are not squares." The beginning of above explanation is sometime when a child learns to differentiate a table from a chair and learns to ignore the fact that they both have four legs which in fact are not important in differentiating a chair from a table. The same child will however identify both chair and table as furniture distinctly different from say a car. Use of pictures, verbal description and constant acquaintance with these objects make these nonmathematical concepts pretty clear for most children. Unfortunately, with respect to most mathematical concepts, making the child aware of say, number 3 is not that easy. We can show 3 cars, 3 apples and 3 dogs but identifying the common threeness in the pictures of cars, apples and dogs is largely left to the child. There is not an easy way to tell the child that the "three" is common to 3 cars, 3 apples and 3 dogs. If the child sees them as "things" then he/she missed the concept of "three". Also, important thing to remember is that even grown ups don't always see everything that is shown. So every child doesn't have to see the idea right after it is explained. There could be several valid reasons for a child not see your point including barriers in communication, child's willingness to be attentive etc. Example 2: The commutative law of addition a + b = b + a is introduced to the child by dividing 15 marbles in to two groups say 10 marbles and 5 marbles and then adding 1st group in the 2nd group and vice versa and then counting to show that the result is 15 marbles. The concept here is the sum of two numbers is not affected by the order in which they are added. If this "concept of commutation" is understood then the child doesn't need to be shown 20 + 30 = 30 + 20 again with the help of marbles. Example 3: The commutative law in Example 2 above is normally not questioned with "why" but simply accepted and its reason is known in later grades when field axioms for real numbers are taught only to learn that highly fundamental facts don't have reason. A new concept called "axiom". Bottom line: In earlier years certainly one could learn the basic facts through manipulative and by solving select problems. Particularly after 4th  5th grades it is through the practice of solving well chosen problems that many hidden concepts can be understood. In my experience, that's the way the mathematics and physics are: not only for reading but largely for solving problems (with paper and pencil). In doing all of these activities a wise goal is to keep the child interested in mathematics and the sought after math mastery will come as consequence in due time. Best regards. MPCTutor www.mpclasses.com  AP Calculus, AP Physics, Singapore Math Grades 712  US Central Time: 2:11 PM 5/14/2010

The same notation that you are referring to can be written as C(n.r) or specifically C(6,2) and C(8, 4) for ease of typing (which is accepted method of representation in many textbooks) C(n.r) means number of distinct combination (or groups) possible when each group contains r things out of n things. Please feel free to write back if you need detail answer. But in short, C(6,2) = 6!/[2!(62)!] = 15 C(8,4) = 8!/[4!(84)!] = 70 Thus, total ways = 15 x 70 = 1050 The topic to look for further information on notation is "Permutation and combination from precalculus" . We are currently registering students for online class for PreCalculus at our website. Sample of topic/chapter wise DVDs may also be available. Please send your request if you are interested. Best regards. MPCTutor www.mpclasses.com Contact for Additional Info  AP Calculus, AP Physics, Singapore Math Grades 712  US Central Time: 11:06 AM 5/7/2010

physics help needed please!!
mpcTutor replied to 1cat2ferrets's topic in High School and SelfEducation Board
This is purely math problem  No electricity/No Physics. (except use of P = V x I) I will rewrite the question and solve it. If interpreted problem is same as the original problem, use the solution, otherwise please post original problem as it is in the original source. Problem: 1) How much power does a light bulb connected to a 120V outlet use if it draws 0.5A of current? 2) One kilowatthour is a measure of energy which is equal to 3,600,000J. How many hours would you have to leave on the light bulb from the above problem in order to expend one kilowatthour? (remember that 1W=1J/s) The information in blue is not needed. 3) If one kilowatthour costs $.10, how long would you have to leave the light bulb on from the above problem in order to spend $1.00 on electricity? Solution: 1) Power = 120 V x 0.5 A = 60 Watts = 0.06 KW 2) Let t = time in hours Power consumed = 1 KWH = (0.06 KW) ( t hour) (1) Solving (1) for t t = 1 KWH / 0.06 KW = 16.67 hours (Answer) 3) Given Rate = 0.1 $/KWH Total bill = $1.00 Hence Total KWH = 1/0.1 = 10 KWH So required time = 10 KWH / 0.06 KW = 166.67 hours (Answer) Best regards. MPCTutor  AP Calculus, AP Physics, IITJEE, Singapore Math  US Central Time: 1:19 PM 5/6/2010 
oops found one more
mpcTutor replied to 1cat2ferrets's topic in High School and SelfEducation Board
Agree with other poster. F = 2.304 x 10^28 N (Force of Repulsion) MPCTutor  AP Calculus, AP Physics, Singapore Math (712)  US Central Time: 11:58 AM 5/6/2010