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Christmas riddle involving natural logs


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#1 48820592

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Posted 25 December 2013 - 11:23 AM

Someone gave me this math riddle. Can you help me solve it?

Y = (ln((x/m) - sa))/(r^2)


Thanks,
Mary

#2 avilma

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Posted 26 December 2013 - 02:29 PM

y = (ln((x-msa)/m))/(r^2)

(r^2)y = ln((x-mas)/m)

rry = ln((x-mas)/m)

e^rry = (x-mas)/m

me^rry = x-mas

 

merry xmas


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#3 48820592

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Posted 26 December 2013 - 04:33 PM

Thank you so much!!! I got as far as the 2nd line but did not think to separate the r^2 into rr. Avilma, you are my math hero!