LearnFromHome Posted June 24, 2008 Share Posted June 24, 2008 My ds and I have been trying to figure this out...can someone explain it in lame terms. x^2+BX/A = -C/A from this point the book says to "Take 1/2 of the coefficient of the middle term, square it, and add it to both sides" we'll our problem is how did they end up with this solution: x^2+BX/A+B/2A^2=-C/A+B/2A^2 or how from BX/A end up with B/2A Thank you! Judy Quote Link to comment Share on other sites More sharing options...
Jane in NC Posted June 24, 2008 Share Posted June 24, 2008 My ds and I have been trying to figure this out...can someone explain it in lame terms. x^2+BX/A = -C/A from this point the book says to "Take 1/2 of the coefficient of the middle term, square it, and add it to both sides" we'll our problem is how did they end up with this solution: x^2+BX/A+B/2A^2=-C/A+B/2A^2 or how from BX/A end up with B/2A Thank you! Judy The coefficient of the x term is B/A. (Remember that A and B here represent constants. The variable is x.) Hence 1/2 of the coefficient is 1/2 times B/A or B/2A. Squaring B/2A we have (B/2A)^2--you need those parens. Hope this helps. Jane Quote Link to comment Share on other sites More sharing options...
LearnFromHome Posted June 24, 2008 Author Share Posted June 24, 2008 Jane, Thank you very much...that makes better sense. For some reason I wanted to divide and that was throwing us off. Thank you for giving me back my sanity. Judy Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.